应该是解方程组(x+1)/5=(y-3)/2 3x+4y=32
(x+1)/5=(y-3)/2
2(x+1)=5(y-3)
2x-5y+17=0.(1)
3x+4y=32.(2)
(1)*3-(2)*2,得到
6x-15y+51=0
6x+8y-64=0
-23y+115=0
y=5
将结果代入(1)
x=4