证明：任意取m＞n,则f(m)-f(n)=m³+3-n³-3=m³-n³=(m-n)(m²+mn+n²)=(m-n)[(m+n/2)²+(3/4)n²]显然m-n＞0,(m+n/2)²≥0,(3/4)n²≥0∴f(m)-f(n)≥0∴f(m)≥f(n)∴f(x)...