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(x^2y/4a)^2 / (-y/2ax)^2 * (-2x/ay)^4
人气:220 ℃ 时间:2020-05-06 19:16:17
解答
(x^2y/4a)^2 / (-y/2ax)^2 * (-2x/ay)^4
= x^4y^2/16a^2*4a^2x^2/y^2*a^4y^4/16x^4
=a^4x^2y^4/64
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