f(x)=[(1+x)/(1-x)]e^(-ax)求导
人气：138 ℃ 时间：2020-06-18 02:26:36
解答
f'(x) = [(1+x)/(1-x)]'e^(-ax) + (-ae^-ax)[(1+x)/(1-x)]= [(1+x)/(1-x)]'e^(-ax) - ae^(-ax) * (1+x)/(1-x)= [-(x-1+2)/(x-1)]'e^(-ax) - ae^(-ax) * (1+x)/(1-x)= [-(x-1)/(x-1)-2/(x-1)]'e^(-ax) - ae^(-ax) * (...
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