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x^2+x-6分之x^2+3x-x^2-4分之x+2计算
人气:321 ℃ 时间:2020-03-20 05:54:40
解答
原式=(x^2+3x)/(x^2+x-6)-(x+2)/(x^2-4)
=x(x+3)/(x+3)*(x-2)-(x+2)/(x+2)*(x-2)
=x/(x-2)-1/(x-2)
=(x-1)/(x-2)
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