> 数学 >
计算,要有过程1/(5a-20)+5/(a²-9a+20)
人气:394 ℃ 时间:2020-04-11 19:45:39
解答
1/(5a-20)+5/(a²-9a+20)
=1/[5(a-4)]+5/[(a-4)(a-5)]
=[(a-b)+25]/[5(a-4)(a-5)]
=(a-b+25)/(5a²-45a+100)
很高兴为您解答,【the 1900】团队为您答题.
请点击下面的【选为满意回答】按钮.��һ��[(a-b)+25]/[5(a-4)(a-5)]��ʲô��˼公分母是:5(a-4)(a-5)通分的过程!
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版