若函数z=z(x,y)由方程y*z^2-x*z=1确定,则Ez/Ex= （这里的E是那个像e上下左右颠倒的符号.）.求过程
人气：326 ℃ 时间：2020-05-14 13:10:45
解答
方程两边同时对x求导得：y(2z∂z/∂x)-(z+x∂z/∂x)=0
∴∂z/∂x=z/(2yz-x)
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