> 数学 >
求lim(sin1/x+cos1/x)^x,其中X趋向于无穷
人气:422 ℃ 时间:2020-01-14 16:24:03
解答
令t=1/x,t趋于0
lim(sint+cost)^(1/t)
=lim[1+(sint+cost-1)]^{[1/(sint+cost-1)]*(sint+cost-1)/t}
再因为t趋于0时,lim(sint+cost-1)/t=lim(cost-sint)=1
所以
lim(sint+cost)^(1/t)
=lim[1+(sint+cost-1)]^{[1/(sint+cost-1)]*(sint+cost-1)/t}
=e
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版