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(1)a^1/2*a^1/3*a^1/4 (2)log³₂·log₃5·log₃2 (3)5^(lg5+lg2-1)
(1)a^1/2*a^1/3*a^1/4
(2)log³₂·log₃5·log₃2
(3)5^(lg5+lg2-1)
人气:263 ℃ 时间:2020-01-28 02:25:22
解答
(1)a^1/2*a^1/3*a^1/4
=a^(1/2+1/3+1/4)
=a^13/12
(2)log³₂·log₃5·log₃2
=lg2/lg3*lg5/lg3*lg2/lg3
=无法计算
(3)5^(lg5+lg2-1)
=5^(1-1)
=5^0
=1
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