已知弧长与弦长,求弓形面积,例如弦长为L=6,弧长为C=2π,求弓形面积S?弧半径为R,弧所对的圆心角为A.L=6,C=2π=6.28319Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*RnR0=5R1=5.6661R2=5.9574R3=5.9992R4=6R5...不怎么满意