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(lg2)²+lg2·lg50+lg25=
人气:334 ℃ 时间:2020-06-10 13:47:43
解答
(lg2)²+lg2·lg50+lg25=
=(lg2)²+lg2·(1+lg5)+2lg5
=(lg2)²+lg2lg5+lg2+2lg5
=lg2(lg2+lg5)+lg2+2lg5
=lg2*lg10+lg2+2lg5
=lg2+lg2+2lg5
=2(lg2+lg5)
=2lg10
=2
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