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约分:-20a²b分之5ab;x²-4分之x²-2x;x+y分之x³-xy²;
x²-2x+1分之1-x²
人气:202 ℃ 时间:2020-04-10 04:54:57
解答
-20a²b分之5ab;5ab/-20a²b=-1/(4a)x²-4分之x²-2x; (x²-2x)/(x²-4)=(x(x-2))/((x+2)(x-2)=x/(x+2)x+y分之x³-xy² (x³-xy²)/(x+y)=(x(x+y)(x-y))/(x+y)=x(x-y)x&...
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