tan(-35π/6)·sin(-46π/3)-cos(37π/6)·tan(55π/6)=?
要过程
人气:343 ℃ 时间:2020-07-17 13:17:17
解答
原式=tan(π/6-6π)·sin(2π/3-16π)-cos(π/6+6π)·tan(π/6+6π)
=tan(π/6)·sin(2π/3)-cos(π/6)·tan(π/6)
=tan(π/6)·sin(π/3)-cos(π/6)·tan(π/6)
=tan(π/6)·cos(π/6)-cos(π/6)·tan(π/6)
=0
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