嗯.我来给你解答吧：原式=x^3*sinx|(1,-1)-∫(1,-1)(3x^2sinx)dx=sin1-(-sin(-1))-[(-3x^2cosx)|(1,-1)-∫(1,-1)(-6xcosx)dx=-[-3cos1+3cos(-1)]+(-6xsinx)|(1,-1)-∫(1,-1)(-6sinx)dx=[-6sin1-6(sin-1)]+(-6cosx)|(...