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求函数y=sin^2(x)的微分
人气:264 ℃ 时间:2020-03-28 03:55:10
解答
y=sin^2(x)
dy
=d[sin^2(x)]
=2sin(x)d[sin(x)]
=2sin(x)cos(x)dx
=sin(2x)dx
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