计算[(x²-5x+6)/(x²-4x+3)]+[(x²-4x+3)/(x²-2x+1)]+[(x²-3x-4)/(1-x²)]
人气:348 ℃ 时间:2019-08-20 21:57:04
解答
=(x-2)(x-3)/(x-3)(x-1)+(x-3)(x-1)/(x-1)²-(x-4)(x+1)/(x+1)(x-1)
=(x-2)/(x-1)+(x-3)/(x-1)-(x-4)/(x-1)
=(x-2+x-3-x+4)/(x-1)
=(x-1)/(x-1)
=1
推荐
- 计算[(x²-5x+6)/(x²-4x+3)]+[(x²-4x+3)/(x²-2x+1)]+[(x²-3x-4)/(1-x²)]
- (要过程)计算:2X²-5X+X²+4X-3X²-2
- 阅读下列计算过程:4x²+2x-1-kx²+3x+2=(4-k)x²+5x+1
- 先化简再求值:5x²-[3x-2(2x-3)-4x²],其中x=-1/2
- 观察下列单项式:x²,-2x³,3x^4,-4x^5,5x^6……
- 设y1=3y+1/3,y2=4-3y/6,若y1+3y2=-1/6,求y的值(请打出可以写在考卷上的步骤) 要快哦~我给50分,可以加!
- 一根铁丝长20厘米,把它对折2次,想一想它被分成了几段,每段长几厘米?
- 六年级数学.急!今晚要有答案!
猜你喜欢