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比较大小:sin(-15π/8)-----sin(-14π/9)
tan89°-----tan91°
人气:232 ℃ 时间:2020-06-13 06:03:36
解答
sin(-15π/8)大于sin(-14π/9)
tan89°大于tan91°过程sin(-15π/8)=sin(-2π+π/8)=sin(π/8)sin(-14π/9)=sin(-2π+4π/9)=sin(4π/9)因为sin在0到π2上是增函数所以sin(-15π/8)小于sin(-14π/9) 额,抱歉刚才的答案有点错tan89°大于0,tan91°小于0所以tan89°大于tan91°
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