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(1/2-1/4+1/6-1/8+1/10-1/12+……+1/198-1/200)÷(1/51+1/52+1/53+1/54+……1/100)
人气:198 ℃ 时间:2019-08-18 22:58:18
解答
1/2-1/4+1/6-1/8+1/10-1/12+…+1/198-1/200 =(1-1/2+1/3-1/4+ ...+1/99-1/100)/2 =[(1+1/2+ ...+1/99+1/100)-2(1/2+1/4+ ...+1/98+1/100)]/2 =[(1+1/2+ ...+1/99+1/100)-(1+1/2+ ...+1/49+1/50)]/2 =(1/51+1/52+1/53...
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