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limx->1求极限(x/x-1 - 1/lnx)
人气:276 ℃ 时间:2019-09-27 13:19:00
解答
lim(x->1)[ x/(x-1) - 1/lnx ]
=lim(x->1) [xlnx-(x-1)]/[(x-1)lnx] (0/0)
= lim(x->1) [ (1+lnx-1) / (lnx + (x-1)/x) ]
= lim(x->1) [ xlnx/(xlnx+(x-1) ] (0/0)
= lim(x->1) [ (lnx+1)/(x+1+1) ]
=1/2
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