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因式分解:(x^2+2x-10)(x^2+2-18)-20
人气:143 ℃ 时间:2020-05-14 10:43:06
解答
(x^2+2x-10)(x^2+2-18)-20
=(x^2+2x-10)(x^2+2x-10-8)-20
=(x^2+2x-10)^2-8(x^2+2x-10)-20
=(x^2+2x-10-10)(x^2+2x-10+2)
=(x^2+2x-20)(x^2+2x-8)
=(x^2+2x-20)(x+4)(x-2)
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