{(x-3)^2-(y+2)^2=(x+y)(x-y) {2x+y=2 [(x-3)-(y+2)][(x-3)+(y+2)]=(x+y)(x-y) (x-y-5)(x+y-1)=(x+y)(x-y) -x+y-5x-5y+5=0 6x+4y-5=0 又 2x+y=2 解得 x=3/2 y=-1是这样子吧！？好评哦！！？^ω^