求不定积分∫xf(x2)f'(x2)dx=?_数学解答

求不定积分∫xf(x2)f'(x2)dx=?

人气：155 ℃　时间：2020-06-26 03:31:55

解答

∫xf(x^2)f'(x^2)dx
=(1/2)∫f(x^2)f'(x^2)dx^2
=(1/2)∫f(x^2)df(x^2)
=(1/4)[f(x^2)]^2+C