(2+0.5)的8次方如何算_数学解答

(2+0.5)的8次方如何算

人气：397 ℃　时间：2019-12-09 07:15:18

解答

(2+0.5)^8
=[(2+1/2)^2]^4
=[4+(1/4)+2]^4
={[6+(1/4)]^2}^2
=[36+(1/16)+3^2
=[39+(1/16)]^2
=1521+(1/256)+(39/8)
=1 525.87890625