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求式子I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I=
I1/5-150/559I+I150/559-1/3I-I-1/3I用合理的方法算
人气:347 ℃ 时间:2020-06-26 14:08:43
解答
I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I
=1/2-1/3+1/3-1/4+1/4-1/5+……+1/9-1/10
=1/2-1/10
=2/5I1/5-150/559I+I150/559-1/3I-I-1/3I用合理的方法算I1/5-150/559I+I150/559-1/3I-I-1/3I=150/559-1/5+1/3-150/559-1/3=-1/5若实数a、b满足a/IaI+b/IbI=0,则ab/IabI=1/6+1/12+1/20+1/30+1/42+1/56=若实数a、b满足a/IaI+b/IbI=0,a+b=0a=-b则ab/IabI=-11/6+1/12+1/20+1/30+1/42+1/56=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8=1/2-1/8=3/8若实数a、b满足a/IaI+b/IbI=0,a+b=0a=-b则ab/IabI=-11/6+1/12+1/20+1/30+1/42+1/56=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8=1/2-1/8=3/8若a=2004/2003,b=2003/2002,c=2002/2001,则a、b、c的关系是用>符号连接a=2004/2003,b=2003/2002,c=2002/2001,a
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