n混=22.4/22.4=1mol
M=40/1=40g/mol
CO 28 4
40
CO2 44 12
所以CO与CO2的物质的量比为：4:12=1:3
所以n (CO)=1mol*(1/4)=0.25mol
n(CO2)=1-0.25=0.75mol
m(CO2)=0.75*44=33g
CO--------------C-------------O CO2-------------C----------------2O
1mol 1mol 1mol 1mol 1mol 2mol
0.25mol x=0.25mol y=0.25mol 0.75mol x=0.75mol y=1.5mol
n(C)=0.25+0.75=1mol n(O)=0.25+1.5=1.75mol
碳原子与氧原子的个数比为:1:1.75=4:7