分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)_数学解答

分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)

人气：326 ℃　时间：2019-11-19 00:51:47

解答

(x-9)/(x-7)-(x+1)/(x-1)=(x-8)/(x-6)-x/(x-2)[(x-9)(x-1)-(x+1)(x-7)]/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]/[(x-6)(x-2)][x^2-10x+9-x^2+6x+7]/(x^2-8x+7]=(x^2-10x+16-x^2+6x]/[x^2-8x+12](-4x+16)/(x^2-8x+7)=(-4x+...