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数学
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若x+2y+3z=10,4x+3y+2z=15,则x+y+z的值为( )
A. 2
B. 3
C. 4
D. 5
人气:141 ℃ 时间:2020-06-23 03:11:19
解答
由题意,x+2y+3z=10①,4x+3y+2z=15②,
①+②,得:5(x+y+z)=25,即x+y+z=5;
故选D.
推荐
3x-2y+z=3 2x+y-z=4 4x+3y+2z=-10
①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-6=0③x/3=y/2 y/4=z/5 x+y+z=60
若x+2y+3z=10,4x+3y+2z=15,则x+y+z的值为( ) A.2 B.3 C.4 D.5
(1)x+y-z=0 2x-y+3z=2 x-4y-2z+6=0(2)3x+y=6 x+2y-z=5 5x-3y+2z=4(3)x+y+z=-1 4x-2y+3z=5 y-z=8-2x
解方程组(1)x+y−z=6x−3y+2z=13x+2y−z=4;(2)x+y=3y+z=5x+z=6.
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