
AB=a,CD=b,由△AOF∽△CEF得
| OF |
| FE |
| AO |
| ED |
| f |
| FE |
| ||
|
| b |
| a |
那么光屏到凸透镜的距离为FE+OF=
| b |
| a |
| b |
| a |
(2)当一束与主光轴平行的光束经凸透镜折射后,还没有汇聚在焦点上时,即在焦点的左侧时,如下图所示:

AB=a,CD=b,由△AOF∽△CEF得
| AO |
| CE |
| OF |
| EF |
| ||
|
| f |
| EF |
| b |
| a |
那么光屏到凸透镜的距离为OF-FE=f-
| b |
| a |
| b |
| a |
故选BD.
A. (1+a/b)f
| OF |
| FE |
| AO |
| ED |
| f |
| FE |
| ||
|
| b |
| a |
| b |
| a |
| b |
| a |

| AO |
| CE |
| OF |
| EF |
| ||
|
| f |
| EF |
| b |
| a |
| b |
| a |
| b |
| a |