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1x2+2x3+3x4+.+100x101=
人气:215 ℃ 时间:2020-03-20 16:36:12
解答
1x2+2x3+3x4+.+100x101= 的通项公式An=n*(n+1)=n²+n 前n项和Sn=(1²+2²+……+n²)+(1+2+……+n) =n(n+1)(2n+1)/6+n(n+1)/2 所以 1x2+2x3+3x4+.+100x101=S(100) =100*101*201/6+100*101/2=34340...
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