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((a+1)(b+1))/(x+2)+((a-1)(b-1))/(x-2)=2ab/x无解,这里实数a、b满足a≠b,ab≠0,则b/a+a/b的值是
人气:155 ℃ 时间:2020-05-13 05:47:08
解答
通分得:(a+1)(b+1)(x-2)x+(a-1)(b-1)(x+2)x=2ab(x+2)(x-2)整理得:x^2-2(a+b)+4ab=0 即(x-2a)(x-2b)=0那么x=2a或x=2b是方程的两个解 若原方程[(a+1)(b+1)]/(x+2)+[(a-1)(b-1)]/(x-2)=2ab/x无解那么x=2,-2或者0则原...
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