(1)1/(x-3)+1/(x+3)=(x+3+x-3)/[(x-3)(x+3)]=2x/(x^2-9)2x/(x^2-9)=4/(x^2-9）,所以2x=4,x=2.x不等于3或-3,所以有解2.(2)方程左边=(4+x-2)/(x^2-2x),方程右边=2/(x-2)=2x/(x^2-2x)所以x+2=2x,x=2.但x=2时,分母=0,所...