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化简:
(1)(xy−y2
x2−2xy+y2
xy
x−y
x2

(2)
a−1
a−2
÷
a2−2a+1
2a−4
人气:361 ℃ 时间:2020-04-03 01:41:53
解答
(1)原式=y(x-y)•
xy
(x−y)2
x−y
x2
=
y2
x

(2)原式=
a−1
a−2
2(a−2)
(a−1)2
=
2
a−1
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