解不等式-4＜x2-5x+2，整理得x2-5x+6＞0，解得{x|x＞3或x＜2}；解不等式x2-5x+2＜26，整理得x2-5x-24＜0，解得{x|-3＜x＜8}；∴不等式-4＜x2-5x+2＜26的解集为{x|x＞3或x＜2}∩{x|-3＜x＜8}={x|-3＜x＜2或3＜x＜8}；...