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数学
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f(x)=x^2x 求导
人气:341 ℃ 时间:2020-04-26 18:04:01
解答
y=f(x)=x^2x
lny=2xlnx
对x求导
(1/y)*y'=2*lnx+2x*1/x=2lnx+2
所以y'=y*(2lnx+2)
所以f'(x)=x^2x(2lnx+2)
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