1/(x+2)-m=(x-m)/(x-2)两边乘(x+2)(x-2)x-2-m(x+2)(x-2)=(x-m)(x+2)x-2-mx²+4m=x²+(2-m)x-2m无解,则这个方程无解或者增根(m+1)x²+(1-m)x+2-6m=0m=-1,2x+8=0,x=-4,有解m≠-1,是二次方程则判别式小于0...