解x³-2x+1=0x³-x²+x²-x-x+1=0(x³-x²)+(x²-x)-(x-1)=0x²(x-1)+x(x-1)-(x-1)=0(x-1)(x²+x-1)=0∴x-1=0或x²+x-1=0∴x=1或x=(-1±√5)/2