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三道四则混合运算数学题
5又5/6+4.5-10又1/3
[20%+(2-1.4)]÷3/20
2/5÷[(2又1/2-1又1/3)÷1又1/6]
人气:211 ℃ 时间:2019-12-24 13:35:48
解答
(1)5又5/6+4.5-10又1/3
=35/6+9/2-31/3
=35/6+27/6-62/6
=62/6-62/6
=0
(2)[20%+(2-1.4)]÷3/20
=(0.2+2-1.4)*20/3
=0.8*20/3
=16/3
(3)2/5÷[(2又1/2-1又1/3)÷1又1/6]
=2/5÷[(5/2÷4/3)÷7/6]
=2/5÷(7/6÷7/6)
=2/5÷1
=2/5
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