函数y=-sin^2x+sinx+4/7的最小值
人气:114 ℃ 时间:2020-02-15 09:34:07
解答
y=-sin^2x+sinx+4/7
=-(sinx)^2+sinx+4/7
=-(sinx-1/2)^2+1/4+4/7
=-(sinx-1/2)^2+23/28
-1不好意思,是函数y=-sin^2x+sinx+7/4的最小值一样的做法。y=-sin^2x+sinx+7/4=-(sinx)^2+sinx+7/4=-(sinx-1/2)^2+1/4+7/4=-(sinx-1/2)^2+2-1<=sinx<=1最小值当sinx=-1时,y=-1/4
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