7 *(2/3)log2(3)=alog2(3)=3a/14log3(2)=14/(3a)log3(5)=blg2=log3(2)/log3(10)=log3(2)/[log3(2)+log3(5)]=[14/(3a)]/[14/(3a)+b]=14/(14+3ab)lg3=1/log3(10)=1/[log3(2)+log3(5)]=1/[14/(3a)+b]=3a/(14+3ab)lg5=1-...