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设x=√3 -2,则x^6+3x^5+11x^3+2x+1=_____
人气:461 ℃ 时间:2019-11-12 01:27:08
解答
x^6+3x^5+11x^3+2x+1
=x^3*(x^3+3x^2+11)+2x+1
=x^3*[(x^2*(x+3)+11]+2x+1
=x^3*[(x^2*(√3 -2+3)+11]+2x+1
=x^3*[(x^2*(√3 +1)+11]+2x+1
=x^3*[(√3 -2)*(√3 -2)*(√3 +1)+11]+2x+1
=x^3*[(√3 -2)*(1-√3)+11]+2x+1
=x^3*[(√3 -2)*(1-√3)+11]+2x+1
=x^3*[-5+3√3+11]+2x+1
=x^3*(6+3√3)+2x+1
=3x^3*(2+√3)+2x+1
=3*(√3 -2)*(√3 -2)*(√3 -2)*(√3+2)+2x+1
=-3*(√3 -2)*(√3 -2)+2*(√3 -2)+1
=-3*(7-4√3)+2√3 -3
=-24+14√3
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