若a,b互为相反数c,d互为倒数求20分之1【a+b+20】+cd的值
人气：496 ℃ 时间：2020-04-10 05:56:55
解答
若a,b互为相反数c,d互为倒数
a+b=0
cd=1
20分之1【a+b+20】+cd
=1/20×(0+20)+1
=1+1
=2
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