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请问(2/2009+4/2009+6/2009+···+2008/2009)—(1/2009+3/2009+5/2009+···+2007/2009)等于多少?
人气:218 ℃ 时间:2019-12-07 19:18:15
解答
(2/2009+4/2009+6/2009+···+2008/2009)—(1/2009+3/2009+5/2009+···+2007/2009)=[(2+4+6+...+2008)-(1+3+5+...+2007)]/2009=[(2-1)+(4-3)+(6-5)+...+(2008-2007)]/2009=1004/2009
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