f(x)=sin2x+2√2cos(π/4+x)+3=2sinxcosx+2cosx-2sinx+3=2sinxcosx+2cosx-2sinx-2+5=2(sinx+1)(cosx-1)+5sinx+1≥0,cosx-1≤0所以(sinx+1)(cosx-1)≤0,原式最大值为5.此时(sinx+1)(cosx-1)=0,即sinx=-1或者cosx=1所...