实数a,b满足根号(2a-3b)+(2a-b-1)^2=0,则根号(ab)*根号(a/b)=
人气:358 ℃ 时间:2019-10-24 13:53:35
解答
∵√﹙2a-3b﹚≥0, ﹙2a-b-1﹚²≥0又: √﹙2a-3b﹚+﹙2a-b-1﹚²=0 ∴ 2a-3b=02a-b-1=0 解得:a=3/4 b=1/2∴√ab·√﹙a/b﹚=√a²=a...
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