已知-x²+3/2x+5=0,求2x²-3x-1/（2x²-3x+2）²
人气：260 ℃ 时间：2020-04-17 05:21:00
解答
-x^2+3x/2+5=02(-x^2+3x/2)=2*-5-2x^2+3x=-10 2x^2-3x=10
(2x^2-3x-1)/(2x^2-3x+2)^2=(10-1)/(10-2)^2=9/64
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