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化简:(x+1)分之1-(x的平方-1)分之(x+3)×(x的平方+4x+3)分之(x的平方-2x+1)
人气:191 ℃ 时间:2019-11-05 09:05:50
解答
原式=1/(x+1)-(x+3)/(x+1)(x-1)乘以(x-1)²/(x+1)(x+3)
=1/(x+1)-1/(x+1)乘以(x-1)/(x+1)
=[(x+1)-(x-1)]/(x+1)²
=2/(x²+2x+1)
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