已知Sn是等比数列{an}的前n项和,a2.a8,a5成等差数列.求等比数列{an}的公比q
人气:204 ℃ 时间:2019-10-23 03:44:50
解答
a2=a1*q,a5=a1*q^4,a8=a1*q^7.
a2.a8,a5成等差数列.
2*a1q^7=a1*q+a1*q^4
2q^7=q+q^4
2q^3=1+q^3
令q^3=t
2t^2=1+t
t1=3/2,t2=-1
q=-1或q=3/2开3次方
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