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求SinX的平方乘以X定积分下限0上限π
人气:282 ℃ 时间:2020-03-14 06:38:16
解答
x(sinx)^2=x*(1-cos2x)/2=1/2*x-1/2xcos2x∫x(sinx)^2dx=1/2∫xdx- 1/2∫xcos2xdx=1/4x^2 -1/4∫xdsin2x=1/4x^2-1/4(xsin2x-∫sin2xdx)=1/4x^2-1/4xsin2x+1/4∫sin2xdx=1/4x^2-1/4xsin2x-1/8cos2x+c把π带入即可...
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