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计算:log16(√128)lolg8(27)log9(16)
请各位计算这三道题..
麻烦各位写出全过程..谢谢...
人气:147 ℃ 时间:2020-10-02 00:02:21
解答
log16(√128)
=log2^4[2^(7/2)]
=(7/2)/4
=7/8
log8(27)
=log2^3(3^3)
=log2(3)
log9(16)
=log3^2(2^4)
= (4/2)log3(2)
=2log3(2)
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