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已知数a<0,ab<0,化简|a-b-3|-|4+b-a|的结果是( )
A. -1
B. 1
C. 7
D. -7
人气:358 ℃ 时间:2020-04-16 10:34:17
解答
根据数a<0,ab<0,可知b>0,
则a-b-3<0,4+b-a>0,
∴|a-b-3|-|4+b-a|=-a+b+3-4-b+a=-1.
故选A.
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